# Score Z Scores Z Research Proposal

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SAMPLE EXCERPT . . .

33

P= Area of the curve beyond 1.33

=0.0918 or 9.18%

b) Less than 80 minutes

Using formula Z=X-? + ?

Z=50-60/15

=10/15

=-0.67

P= Area of the curve below -0.67

P=0.2514

%=25.14%

Between 45-75

Using the formula Z=X-? + ?

Z (45) =45-60/15

=-1

Z (75) = 75-60/15

=1

P between -1 and 1

= 0.3413 + 0.3413

=0.6826

% =68.26%

Question 3

Bob takes an online IQ test and finds that his IQ according to the test is 134. Assuming that the mean IQ is 100, the standard deviation is 15, and the distribution of IQ scores is normal, what proportion of the population would score higher than Bob? Lower than Bob?

Proportion higher than Bob would be the area of the curve beyond Bob's score, the proportion lower than Bob would be the area of the curve below Bob's score.

Using the formula Z=X-? + ?

Z =134-100/15

=34/15

=2.27

P Higher than Bob's Score = 0.0116

P Lower than Bob's Score =0.9984Buy full paper

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33

P= Area of the curve beyond 1.33

=0.0918 or 9.18%

b) Less than 80 minutes

Using formula Z=X-? + ?

Z=50-60/15

=10/15

=-0.67

P= Area of the curve below -0.67

P=0.2514

%=25.14%

Between 45-75

Using the formula Z=X-? + ?

Z (45) =45-60/15

=-1

Z (75) = 75-60/15

=1

P between -1 and 1

= 0.3413 + 0.3413

=0.6826

% =68.26%

Question 3

Bob takes an online IQ test and finds that his IQ according to the test is 134. Assuming that the mean IQ is 100, the standard deviation is 15, and the distribution of IQ scores is normal, what proportion of the population would score higher than Bob? Lower than Bob?

Proportion higher than Bob would be the area of the curve beyond Bob's score, the proportion lower than Bob would be the area of the curve below Bob's score.

Using the formula Z=X-? + ?

Z =134-100/15

=34/15

=2.27

P Higher than Bob's Score = 0.0116

P Lower than Bob's Score =0.9984Buy full paper

for $19.77

## Research Proposal on *Score Z Scores Z-Scores the* Assignment

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